The several products added together will be the true product. NOTE. Sometimes it will be easier to take parts with inches, &c. instead of multiplying by them. Ans. 1502 9 2 7 5. A floor is 18 feet, 7 inches long, and 16 feet, 9 inches wide, what is the area of the floor? Ans. 311 F. 3' 3". 6. What is the area of a floor, which is 26 feet, 3 inches long, and 9 feet, 9 inches wide ? Ans. 255 F. il' 3". 7. A roof of a building measures 52 feet, 7 inches, by 56 feet, 3 inches, how many squares of 100 superfi. cial feet each does this roof contain ?* Ans. 29. squares, 57 F. 9' 9". * Flooring and roofing are done by the square of 100 superficial feet. Some partitions and ceilings are done by the square yard of 9 superficial feet each : also, plastering, paving, and painting, are done by the square yard. 8. A mason has paved a part of a street, which measures in length 236 feet, 8 inches, and in breadth 37 feet 8 inches ; how many square yards does it contain ? Ans. 990 yds. 4 F. 5'. 9. A carpenter has ceiled the sides of a store, the walls of which are 9 feet, 10 inches high, and 150 feet, 6 inches about, and to be paid by the square yards ; how many yards must he be paid for ? Ans. 164 yds. 3 F. 11". 10. A mason has plastered 3 rooms, the ceiling of each is 20 feet by 16 feet, and the walls of each, 91 feet high, and 73 feet about ; there is to be 90 yards deducted for doors, windows, chinneys, &c, from the whole ; how many yards must he be paid for? Ans. 251 yds. 1 F. 6'. 11. A painter has painted the side of a building 40 feet long, 27{ feet high, (no deduction) how much will the painting come to, at 40 cents per yard ? Ans. $48,88,8. DUODECIMALS APPLIED TO CUBIC MEASURE. Stone walls of cellars, &c. are laid by the perch of 24 cubic feet each, the number of perches are found by first finding the number of solid (or cubic) feet ; then multiply the cubic feet by 4, to reduce them to quarters, and divide the product by 99 (the number of quarters in 24%) the quotient will be perches; the remainder so many ninety-ninths of a perch. The cubic feet in a wall, or any other thing, are found by multiplying the length, breadth, and height together. EXAMPLES. 1. In a cellar wall which is 9 feet high, 24 feet thick, and the sides and ends together, were 131 feet, 5 inches, in length ; how many perches did it contain ? 46 Timber and some kinds of stone are bought and sold by the solid (or cubic) foot, the contents being found by multiplying the length, breadth, and thickness together ; timber is sometimes bought and sold by the ton. 2. A stone is 5 feet inches long, 3 feet 7 inches wide, and 2 feet 9 inches thick ; 'required the number of cubic feet it contains. Ans. 51 F. 8' 9" 9". 3. How many cubic feet in a piece of timber 37 feet long, 1į foot wide, and I foot 3 inches thick ? Ans. 69 F. 4' 6". 4. What will 9 pieces of timber come to, at $2,50 per ton, each piece being 294 feet long, 1 foot 9 inches, by I foot 7 inches, the side widths. Ans. 836,78+. Diggers and fillers up of docks, wharves, &c. work by the square of 6 feet long, wide and deep, making 216 cubic feet to a square. 5. How many squares have been dug out of a cellar, 41 feet long, 21{ feet wide, and 8 feet 9 inches deep? Ans. 35 squares, 153 F. 1'6". 6. A dock has been filled, which was 126 feet 7 inches long, 50 feet 4 inches wide, and 121 feet deep ; how much does it come to at $2,75 per square ? Ans. $1013,96116. The freight of bales, boxes, chests, trunks, &c, is cominonly paid so much per cubic foot, or so much per ton. 7. How many cubic feet are in a box 71 feet long, 4 feet 2 inches wide, and 3 feet 4 inches deep? Ans. 104F. 2'. 8. How many tons (40 cubic feet to the ton) are in 7 bales, each 5 feet, 9 inches long, 4 feet wide, and 3 feet 5 inches thick ? Ans. 13 tons, 30 F. 1'. 9 How much must be paid for the freight of 11 trunks, each being 4 feet long, I foot 7 inches wide, and I foot 4 inches deep, at $15,25, per ton ? Ans. $35,41,3,15 Grindstones are sold by the cubic foot, called a stone. To find the number of stones (or cubic feet) contained in a grindstone, having the diameter and thickness given in inches. RULE. Multiply the diameter by itself, then multiply this product by 11, divide the second product by 14, the quotient will be the superficial area of its side ; then multiply this area by the thickness of the stone, in inches, and divide the product by 1728, the quotient will be the number of stones. EXAMPLES. 1. How many stones are contained in a grindstone, its diameter being 36 inches, and 4 inches thick, and what is it worth at $1,25 per stone ? 2 2. What is the value of a grindstone 25 inches diameter, and 6 inches thick, at $1,75 ? Ans. $2,98,3+ 3. Required the value of a grindstone 7 inches thick, and 41 diameter, at $2,10 per stone. Ans. $11,23,5,+ To find the tonage of double decked vessels. RULE Multiply the length of the keel by the breadth on the main beam, and that product by the depth, (all in feet) and divide the last product by 95 for tons. Nore. Half the breadth on the main beam is called the depth of double decked vessels. |